X^2-13x+18=-5x+2

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Solution for X^2-13x+18=-5x+2 equation: 



X^2-13X+18=-5X+2

We move all terms to the left:

X^2-13X+18-(-5X+2)=0

We get rid of parentheses

X^2-13X+5X-2+18=0

We add all the numbers together, and all the variables

X^2-8X+16=0

a = 1; b = -8; c = +16;
Δ = b2-4ac
Δ = -82-4·1·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{8}{2}=4$

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